sin^2x-3cosx=4

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Solution for sin^2x-3cosx=4 equation: 


Simplifying
sin2x + -3cosx = 4

Reorder the terms:
-3cosx + in2sx = 4

Solving
-3cosx + in2sx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1in2sx' to each side of the equation.
-3cosx + in2sx + -1in2sx = 4 + -1in2sx

Combine like terms: in2sx + -1in2sx = 0
-3cosx + 0 = 4 + -1in2sx
-3cosx = 4 + -1in2sx

Divide each side by '-3osx'.
c = -1.333333333o-1s-1x-1 + 0.3333333333in2o-1

Simplifying
c = -1.333333333o-1s-1x-1 + 0.3333333333in2o-1

Reorder the terms:
c = 0.3333333333in2o-1 + -1.333333333o-1s-1x-1

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